PATTERN PRINTING IN C & C++

To print a pattern E of n rows we  print an E with n+1/2 "*" 's at 1st and last row Nd n-1/2 "*" 's at middle

for C++ the code goes here ----------------


#include<iostream>
using namespace std;
int main()
{
int i,j,n;
cout<<"No of Rows : ";
cin>>n;
for(i=1;i<=n;i++)
{
if(i==1 || i==n)
{
for(j=1;j<=(n+1)/2;j++)
{
cout<<"*";
}
cout<<"\n";
}

    else if (i==((n+1)/2))
{
for(j=1;j<=(n-1)/2;j++)
{
cout<<"*";
}
cout<<"\n";
}
else
{
cout<<"*\n";
}

}

}


like this.....

if you run this code with n = 15 then no of row will be 15 ,at 1st line and 15 th line no of "*" will be 

15+1/2=8  and at the middle no of "*" will be 15-1/2 = 7 , like this 

similar code goes for  C 

#include<stdio.h>

#include<conio.h>

int main()

{

int i,j,n;

printf("No of Rows : ",n);

scanf("%d",&n);

for(i=1;i<=n;i++)

{

if(i==1 || i==n)

{

for(j=1;j<=(n+1)/2;j++)

{

printf("*");

}

printf("\n");

}

    else if (i==((n+1)/2))

{

for(j=1;j<=(n-1)/2;j++)

{

printf("*");

}

printf("\n");

}

else

{

printf("*\n");

}

}

}

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